Two things to check here:
·
In the area of the graph to the right of the y-axis, does
one variable increase as the other variable decreases? The area of the graph
to the left of the y-axis is a bit tricky – for , as x decreases (goes
more negative), y gets larger (becomes less negative). However, for
, as x decreases,
y decreases too.
Sponsored Links
· Is the graph undefined at x = 0 (where the y-axis usually is)? This should happen regardless of what type of inverse relationship it is, because there’s a divide by ‘x’ or divide by ‘x2’ or something similar. Since x is zero, dividing by ‘0’ gets you an undefined number. The value of ‘y’ near x = 0 should be either a very large positive number or a very large negative number.
Here’s a heap of graphs that aren’t inverse relationships:
Not inverse relationships |
|
These graphs are inverse relationships:
This graph doesn’t pass through the origin, which is
OK. To the right of the y-axis, as x increases, y decreases, which is OK. To
the left of the x-axis as x decreases, y increases. It also appears that the
value of y gets very large and positive as you approach x = 0 from the right
side of the y-axis. It also seems to get very large and negative when you
approach from the left side of the y-axis. Because the graph is mirror imaged
both across the x-axis and y-axis, it’s probably of the form , or
, or
– the power of x
in the denominator will be an odd number.
This graph doesn’t pass through the origin which is
OK. To the right of the y-axis, as x increases y decreases, which is OK. To
the left of the y-axis, as x decreases, y decreases too. This is OK as well –
it just means that the inverse relationship is going to be like ,
– the power of
‘x’ in the denominator will be an even number (remember that a negative
x raised to an even power will give a positive answer, which makes sense since
all the values of y to the left of the y-axis are positive).